how many more santas could you haul if you took the antlers off your car?

I posted this on LinkedIn earlier (after running the CFD) but thought it deserved some more analysis.

Original Post:
"I assume I'm not the only one who has wondered how much effect those little reindeer antlers have on fuel economy...Anyway, turns out it's not much.

Less than 2 kpa pressure drop across the antler with a minimal downstream eddy. On a giant metal box like this one with a flat grille the relative impact is negligible. Go ahead, decorate your brick however you like."

That answers the question "Is the effect even remotely significant?"(which let's face it, was never in doubt). So I figured it was time for a conversation with Dystr to figure out how much of an effect this additional pressure drop would have on the overall drag coefficient and effective range.

We stayed up chatting long into the night. I asked things like "given the drag coefficient and the operating range of a cybertruck at 40 mph what is the rolling resistance of cybertruck"

To which, Dystr replied "The calculation task exceeded the runtime limit again. To resolve this, I will further optimize the code and attempt to run it once more."

Not what I expected, but whatever...I just let it's do its thing in the background and instead asked...how much force does 2 kPa distributed across an 18"x1" surface produce?"

To which it replied almost immediately, "5.22 lb or 23.23 N"

Given that the rolling resistance of Cybertruck is about .01, this means that adding a set of antlers to the car adds about as much resistive force as an additional 522 lb. of passenger weight. So the obvious question is:

1.898181818181818181818 Santas. You could be hauling 1.898181818181818181818 Santas in your metal brick if you would just take the antlers off.